Convert RTF file to HTML string in C# and .NET
Complete code
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using SautinSoft;
namespace Example
{
class Program
{
static void Main(string[] args)
{
ConvertRtfToHtml();
}
/// <summary>
/// Converts RTF file to HTML string.
/// </summary>
static void ConvertRtfToHtml()
{
string inpFile = @"..\..\..\example.rtf";
string htmlString = String.Empty;
RtfToHtml r = new RtfToHtml();
using (StreamReader inpReader = new StreamReader(inpFile))
{
using (MemoryStream resultStream = new MemoryStream())
{
r.Convert(inpReader.BaseStream, resultStream, new RtfToHtml.HtmlFixedSaveOptions() { Title = "SautinSoft Example." });
htmlString = Encoding.UTF8.GetString(resultStream.ToArray());
}
}
// This file is necessary only to show the result.
string outfile = Path.GetFullPath("Result.html");
File.WriteAllText(outfile, htmlString);
// Open the result for demonstration purposes.
System.Diagnostics.Process.Start(new System.Diagnostics.ProcessStartInfo(outfile) { UseShellExecute = true });
}
}
}
Imports System
Imports System.Collections.Generic
Imports System.Linq
Imports System.Text
Imports System.IO
Imports SautinSoft
Namespace Example
Friend Class Program
Shared Sub Main(ByVal args() As String)
ConvertRtfToHtml()
End Sub
''' <summary>
''' Converts RTF file to HTML string.
''' </summary>
Private Shared Sub ConvertRtfToHtml()
Dim inpFile As String = "..\..\..\example.rtf"
Dim htmlString As String = String.Empty
Dim r As New RtfToHtml()
Using inpReader As New StreamReader(inpFile)
Using resultStream As New MemoryStream()
r.Convert(inpReader.BaseStream, resultStream, new RtfToHtml.HtmlFixedSaveOptions() With {.Title = "SautinSoft Example."})
htmlString = Encoding.UTF8.GetString(resultStream.ToArray())
End Using
End Using
' This file is necessary only to show the result.
Dim outfile As String = Path.GetFullPath("Result.html")
File.WriteAllText(outfile, htmlString)
' Open the result for demonstration purposes.
System.Diagnostics.Process.Start(New System.Diagnostics.ProcessStartInfo(outfile) With {.UseShellExecute = True})
End Sub
End Class
End Namespace
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