Convert Text file to HTML file in C# and .NET


Complete code

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using SautinSoft;

namespace Example
{
    class Program
    {
        static void Main(string[] args)
        {
            ConvertTextToHtml();
        }
        /// <summary>
        /// Converts Text file to HTML file.
        /// </summary>
        static void ConvertTextToHtml()
        {
			// Get your free 100-day key here:   
            // https://sautinsoft.com/start-for-free/
			
            // If you need more information about "RTF to HTML .Net" 
            // Email us at: support@sautinsoft.com.
			
            string inpFile = @"..\..\..\example.txt";
            string outfile = Path.GetFullPath("Result.html");
            
            RtfToHtml r = new RtfToHtml();
            r.Convert(inpFile, outfile, new RtfToHtml.HtmlFixedSaveOptions() {Title = "SautinSoft Example." });

            // Open the result for demonstration purposes.
            System.Diagnostics.Process.Start(new System.Diagnostics.ProcessStartInfo(outfile) { UseShellExecute = true });
        }
    }
}

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Imports System
Imports System.Collections.Generic
Imports System.Linq
Imports System.Text
Imports System.IO
Imports SautinSoft

Namespace Example
	Friend Class Program
		Shared Sub Main(ByVal args() As String)
			ConvertTextToHtml()
		End Sub
		''' <summary>
		''' Converts Text file to HTML file.
		''' </summary>
		Private Shared Sub ConvertTextToHtml()
				    ' Get your free 100-day key here:   
            ' https://sautinsoft.com/start-for-free/
			
            ' If you need more information about "RTF to HTML .Net" 
            ' Email us at: support@sautinsoft.com.
			Dim inpFile As String = "..\..\..\example.txt"
			Dim outfile As String = Path.GetFullPath("Result.html")

			Dim r As New RtfToHtml()
			r.Convert(inpFile, outfile, new RtfToHtml.HtmlFixedSaveOptions() With {.Title = "SautinSoft Example."})

			' Open the result for demonstration purposes.
			System.Diagnostics.Process.Start(New System.Diagnostics.ProcessStartInfo(outfile) With {.UseShellExecute = True})
		End Sub
	End Class
End Namespace

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